(a) Round 73846 to the nearest thousand. →

(b) Round 3.468 to 1 decimal place. →

(c) Round 0.007986 to 2 significant figures. →

(a) 4876 − 1939 =

(b) −3.4 + 7.28 =

(a) 307 × 24 =

(b) 5268 ÷ 12 =

(a) Find $\frac{3}{5}$ of 210. →

(b) $\frac{3}{5}$ of a number is 210. Find the number. →

(a) $\frac{3}{8}+\frac{5}{12}$ =

(b) $\frac{7}{10}-\frac{1}{5}$ =

(a) $\frac{2}{3}\times \frac{15}{28}$ =

(b) $\frac{5}{6}÷\frac{3}{10}$ =

(a) Write 0.375 as a fraction in simplest form and as a percentage: and %

(b) Write $\frac{7}{20}$ as a decimal. →

(c) Write 12% as a fraction in simplest form:

(d) Find 15% of 160. →

By rounding to 1 significant figure, estimate 39.7 × 0.51.

Rounded numbers used: × → Estimate =

(a) Convert: 3.5 kg = g    and   2.4 m = cm

(b) A rope is measured as 8.4 m to the nearest 0.1 m. Give the error interval for its actual length (enter numbers only):

Lower bound = m    Upper bound = m

(a) Write 84 as a product of prime factors (index form allowed). → × ² ³ ⁴ ⁵

(b) Write 60 as a product of prime factors. → × ² ³ ⁴ ⁵

(c) Hence find HCF of 84 and 60. →

(d) Hence find LCM of 84 and 60. →

(a) Evaluate 5³. →

(b) Evaluate √196. →

(c) Hence find 5³ − √196. →

(a) Simplify to a single power of 2: $2^5\times 2^3÷2^4$ = 2 00

(b) Express $96=2^a\times 3^b$ . Give integers a and b: a = , b =

(a) Write 0.00036 in standard form.

(b) Write $5.2\times {10}^4$ as an ordinary number. →

(a) $(3\times {10}^5)\times (2\times {10}^{-3})$ — give your answer in standard form:

(b) $(6\times {10}^7)÷(3\times {10}^2)$ — give your answer in standard form:

(c) $(7\times {10}^6)+(3\times {10}^5)$ — give your answer in standard form: